The unproved formulas of Ramanujan - MathOverflow
Nov 21, 2020 · So Berndt doesn't consider the Brocard-Ramanujan problem to be a "remaining conjecture" of Ramanujan, I guess? Or maybe he was considering only "formulas" because you were …
What did Ramanujan get wrong? - MathOverflow
Dec 13, 2017 · Here is a mistake which was even featured in the Ramanujan movie: in his letters to Hardy, Ramanujan claimed to have found an exact formula for the prime counting function $\pi (n)$, …
The Extended Riemann Hypothesis and Ramanujan's Sum
Apr 4, 2022 · Riemann Hypothesis and Ramanujan’s Sum Explanation RH: All non-trivial zeros of the Riemannian zeta-function lie on the critical line. ERH: All zeros of L-functions to complex Dirichlet …
fa.functional analysis - Ramanujan's Master Formula: A proof and ...
Dec 21, 2020 · Ramanujan's Master Formula: A proof and relation to umbral calculus Ask Question Asked 5 years ago Modified 1 year, 7 months ago
How did Ramanujan come up with the Ramanujan summation and is it ...
Dec 4, 2023 · 0 How did Ramanujan come up with the Ramanujan summation and is it possible to extend it to higher sets (Everything circled in red is what I'm interested in (+ the Cauchy integral to …
The origin of the Ramanujan's $\pi^4\approx 2143/22$ identity
Feb 26, 2016 · What is the origin of the Ramanujan's approximate identity $$\pi^4\approx 2143/22,\;\;\tag 1$$ which is valid with $10^ {-9}$ relative accuracy? For comparison, the relative …
The Chudnovskys' original proof of their $1/\pi$ formula
Mar 3, 2025 · I am trying to understand the famous paper by the Chudnovsky brothers, "Approximations and complex multiplication according to Ramanujan" (reprinted in Pi: A Source Book), which (among …
ho.history overview - What were Ramanujan's standard …
Jun 20, 2020 · Ramanujan had a great skill in algebraic manipulation (much better than current symbolic software). Almost all his independent (of Hardy) work is based on algebraic manipulation. And note …
Ramanujan's series for $ (1/\pi)$ and modular equation of degree $29$
Although Ramanujan mentions a process where this expression can be obtained from a modular equation of degree $29$, but due to the complexity of Russell's modular equation of degree $29$ I …
Asymptotic for Ramanujan's $\tau$-function - MathOverflow
Nov 8, 2023 · 2 I am not too familiar with this stuff but it seems highly unlikely Ramanujan's tau function would have general asymptotics due to its arithmetic functional quality.