Sep 22, 2017 · I put my code in the XML validation website and it gives me this error: Line 8: 4 The markup in the document following the root element must be well-formed. The line that is …

35 You will also get 'root element is missing' when the BOM strikes :). BOM = byte order mark. This is an extra character that gets added to the start of a file when it is saved with the wrong …

The following post asks how to indicate that an element is the root element in an XML schema: Is it possible to define a root element in an XML Document using Schema? I have followed the …

How do I get Jackson's XMLMapper to read the name of the root xml element when deserializing? I am deserializing input XML to generic Java class, LinkedHashMap and then to JSON.

The fact is that the first element is the root element, based on which XmlReader can be used to get the root element. Using XmlReader will be much more efficient than using XmlDocument …

I have seen many implementations of JAXB where we can convert java primitive to XML element using @XmlElement annotation. But, I want to convert following POJO to XML (Note there is …

Feb 5, 2016 · @LittleChild - You will get an XML schema with that has de.vogella.xml.jaxb.model as the target namespace that defines the bookstore element. The problem is that the class …

Also see the Parsing XML with Namespaces section of the ElementTree documentation. As of Python 3.8, the ElementTree library also understands the {*} namespace wildcard, so …

<scowl> changing root element to be of inline type, however, makes all classes to be inner classes of the root type. Also, even if the root element type is defined AFTER the root element …

Jul 1, 2020 · I have problem parse XML in C# because XML not have root element. How can I add root element? When try XDocument show erorrs about root element. Maybe can use some file …